The component of a vector along any other direction is
- Aalways less than its magnitude
- Balways greater than its magnitude
- Calways equal to its magnitude
- DNone of the above
Similar Questions
For component of a vector $A =(3 \hat{ i }+4 \hat{ j }-5 \hat{ k })$, match the following colum.
Colum $I$
Colum $II$
$(A)$ $x-$axis
$(p)$ $5\,unit$
$(B)$ Along another vector $(2 \hat{ i }+\hat{ j }+2 \hat{ k })$
$(q)$ $4\,unit$
$(C)$ Along $(6 \hat{ i }+8 \hat{ j }-10 \hat{ k })$
$(r)$ $0$
$(D)$ Along another vector $(-3 \hat{ i }-4 \hat{ j }+5 \hat{ k })$
$(s)$ None
| Colum $I$ | Colum $II$ |
| $(A)$ $x-$axis | $(p)$ $5\,unit$ |
| $(B)$ Along another vector $(2 \hat{ i }+\hat{ j }+2 \hat{ k })$ | $(q)$ $4\,unit$ |
| $(C)$ Along $(6 \hat{ i }+8 \hat{ j }-10 \hat{ k })$ | $(r)$ $0$ |
| $(D)$ Along another vector $(-3 \hat{ i }-4 \hat{ j }+5 \hat{ k })$ | $(s)$ None |
Define the scalar product of two vectors.
Define the scalar product of two vectors.
For three vectors $\vec{A}=(-x \hat{i}-6 \hat{j}-2 \hat{k})$, $\vec{B}=(-\hat{i}+4 \hat{j}+3 \hat{k})$ and $\vec{C}=(-8 \hat{i}-\hat{j}+3 \hat{k})$, if $\overrightarrow{\mathrm{A}} \cdot(\overrightarrow{\mathrm{B}} \times \overrightarrow{\mathrm{C}})=0$, them value of $\mathrm{x}$ is. . . . . ..
For three vectors $\vec{A}=(-x \hat{i}-6 \hat{j}-2 \hat{k})$, $\vec{B}=(-\hat{i}+4 \hat{j}+3 \hat{k})$ and $\vec{C}=(-8 \hat{i}-\hat{j}+3 \hat{k})$, if $\overrightarrow{\mathrm{A}} \cdot(\overrightarrow{\mathrm{B}} \times \overrightarrow{\mathrm{C}})=0$, them value of $\mathrm{x}$ is. . . . . ..
- [JEE MAIN 2024]
A vector $\vec{A}$ points towards North and vector $\vec{B}$ points upwards then $\vec{A} \times \vec{B}$ points towards ...........
The angle between the two vectors $\overrightarrow A = 5\hat i + 5\hat j$ and $\overrightarrow B = 5\hat i - 5\hat j$ will be ....... $^o$
The angle between the two vectors $\overrightarrow A = 5\hat i + 5\hat j$ and $\overrightarrow B = 5\hat i - 5\hat j$ will be ....... $^o$