What will be the projection of vector A=hat{i | vedclass

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Question

Projection of vector $A$ on vector $B$

$(A \cos 	heta) \hat{B}=A\left(\frac{\bar{A} \cdot \bar{B}}{A B}ight) \hat{B}=\frac{\bar{A} \cdot \bar{B}

Vedclass · Accepted Answer

$(\hat{i}+\hat{j})$

Vedclass · Answer

Projection of vector $A$ on vector $B$

$(A \cos 	heta) \hat{B}=A\left(\frac{\bar{A} \cdot \bar{B}}{A B}ight) \hat{B}=\frac{\bar{A} \cdot \bar{B}}{B} \hat{B}$

$=\frac{2}{\sqrt{2}}\left(\frac{\hat{i}+\hat{j}}{\sqrt{2}}ight)=\hat{i}+\hat{j}$

What will be the projection of vector $A=\hat{i}+\hat{j}+\hat{k}$ on vector $\vec{B}=\hat{i}+\hat{j}$.

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