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p-Block Elements - I
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The compound($s$) which react($s$) with $NH _3$ to give boron nitride ($BN$) is(are)
$(A)$ $B$ $(B)$ $B _2 H _6$ $(C)$ $B _2 O _3$ $(D)$ $HBF _4$
A
$A,B$
B
$B,C$
C
$A,C$
D
$A,D$
(IIT-2022)
Solution
$(A)$ $2 B +2 NH _3 \rightarrow 2 BN +3 H _2$
Boron produced BN with ammonia but Boron is element not compound. So that this option not involve in answer.
$(B) 3$
$3 B _2 H _6+6 NH _3 \rightarrow 3\left[ BH _2\left( NH _3\right)_2\right]^{+}\left[ BH _4^{-}\right] \xrightarrow{ T =200^{\circ} C } 2 B _3 N _3 H _6+12 H _2$
$B _3 N _3 H _6 \xrightarrow{ T >200^{\circ} C }( BN )_{ z }$
$(C)$ $B _2 O _3(\ell)+2 NH _3 \xrightarrow{1200^{\circ} C } 2 BN _{( s )}+3 H _2 O _{( g )}$
$(D)$ $HBF _4+ NH _3 \rightarrow NH _4\left[ BF _4\right]$
Standard 11
Chemistry
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