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10-1.Circle and System of Circles
medium
The coordinates of the radical centre of the three circles ${x^2} + {y^2} - 4x - 2y + 6 = 0,{x^2} + {y^2} - 2x - 4y -1 = 0,$${x^2} + {y^2} - 12x + 2y + 30 = 0$ are
A$(6, 30)$
B$(0, 6)$
C$(3, 0)$
DNone of these
Solution
(d) Radical axis of first two circles is
$6y – 6 = 0$ i.e., $y = 1$….$(i)$
Radical axis of last two circles is
$8x + 2y = 30$….$(ii)$
Solving $(i)$ and $(ii),$ we get radical centre $\left( {\frac{7}{2},\;1} \right)$.
$6y – 6 = 0$ i.e., $y = 1$….$(i)$
Radical axis of last two circles is
$8x + 2y = 30$….$(ii)$
Solving $(i)$ and $(ii),$ we get radical centre $\left( {\frac{7}{2},\;1} \right)$.
Standard 11
Mathematics