7.Gravitation
hard

The correct graph representing the variation of total energy $({E_t})$ kinetic energy $({E_k})$ and potential energy $(U)$ of a satellite with its distance from the centre of earth is

A
B
C
D

Solution

(c) $U = \frac{{ – GMm}}{r},K = \frac{{GMm}}{{2r}}$ and $E = \frac{{ – GMm}}{{2r}}$

For a satellite $U,K$ and $E$ varies with $r$ and also $U$ and $E$ remains negative whereas $K$ remain always positive.

Standard 11
Physics

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