- Home
- Standard 11
- Chemistry
4.Chemical Bonding and Molecular Structure
medium
The correct order of bond dissociation energy among $N_2, O_2, O_2^-$ is shown in which of the following arrangements?
A
$N_2 > O_2^- > O_2$
B
$O_2^- > O_2 > N_2$
C
$N_2 > O_2 > O_2^-$
D
$O_2 > O_2^- > N_2$
(JEE MAIN-2014)
Solution
The bond order of $N_2,$ $O_2,$ and $O_2^-$ are respectively $3,2$ and $1.5$
Since higher bond order implies higher bond dissociation energy hence the correct orde will be
$N_2 > O_2 > O_2^-$
Standard 11
Chemistry
