The correct order of bond dissociation energy among $N_2, O_2, O_2^-$ is shown in which of the following arrangements?
$N_2 > O_2^- > O_2$
$O_2^- > O_2 > N_2$
$N_2 > O_2 > O_2^-$
$O_2 > O_2^- > N_2$
Give $\mathrm{MO}$ diagram and explain $\mathrm{Ne}_{2}$ molecule is not possible.
The bond order is maximum in
Give answer of following questions.
$(i)$ Give molecular orbitals and type form by $\mathrm{LCAO}$ from $2{\rm{s}},2{{\rm{p}}_{\rm{x}}},2{{\rm{p}}_{\rm{y}}}$ and $2{{\rm{p}}_{\rm{z}}}$
$(ii)$ ${\rm{L}}{{\rm{i}}_2},{\rm{B}}{{\rm{e}}_2},{{\rm{C}}_2},{{\rm{N}}_2},{{\rm{O}}_2}{\rm{,}}{{\rm{F}}_2}$ for these molecule give energy other.
According to molecular orbital theory which of the following statement about the magnetic character and bond order is correct regarding $O_2^ + $
The paramagnetic molecule at ground state among the following is