The correct order of bond dissociation energy among $N_2, O_2, O_2^-$ is shown in which of the following arrangements?
$N_2 > O_2^- > O_2$
$O_2^- > O_2 > N_2$
$N_2 > O_2 > O_2^-$
$O_2 > O_2^- > N_2$
Use the molecular orbital energy level diagram to show that $\mathrm{N}_{2}$ would be expected to have a triple bond, $\mathrm{F}_{2}$ a single bond and $\mathrm{Ne}_{2}$ no bond.
The bond order is maximum in
In the conversion of $N_2$ into $N_2^+$ the electron will be lost from which of the following molecular orbital ?
What is meant by the term bond order ? Calculate the bond order of: $N _{2}, O _{2}, $ $O _{2}^{+}$ and $O _{2}^{-}$
Which of the following $M.O$ has two nodal Plane's