The correct order of the $O-O$ bond length in $O_2, H_2O_2$ and $O_3$ is
$O_3 > H_2O_2 > O_2$
$O_2 > H_2O_2 > O_3$
$O_2 > O_3 > H_2O_2$
$H_2O_2 > O_3 > O_2$
as per bond order
Which of the following statement is correct for peroxide ion
$A.$ has completely filled $\pi$ antibonding molecular orbitals $B.$ is diamagnetic $C.$ has bond order one $D.$ is isoelectronic with Neon
Using molecular orbital theory, compare the bond energy and magnetic character of ${\rm{O}}_2^ + $ and ${\rm{O}}_2^{2 – }$ species.
In which pair, or pairs, is the stronger bond found in the first species
$(a)$ $O_2^ – ,{O_2}$ $(b)$ ${N_2},N_2^ +$ $(c)$ $NO^+, NO^-$
In the conversion of $N_2$ into $N_2^+$ the electron will be lost from which of the following molecular orbital ?
The pair of species that has the same bond order in the following is
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