Gujarati
13.Nuclei
easy

The decay constant of radium is $4.28 \times {10^{ - 4}}$ per year. Its half life will be ..........$years$

A

$2000$

B

$1240$

C

$63$

D

$1620$

Solution

(d) $T = \frac{{0.6931 \times 1}}{\lambda } = \frac{{0.6931 \times 1}}{{4.28 \times {{10}^{ – 4}}}}year = 1620\;years$

Standard 12
Physics

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