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13.Nuclei
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The decay constant of radium is $4.28 \times {10^{ - 4}}$ per year. Its half life will be ..........$years$
A
$2000$
B
$1240$
C
$63$
D
$1620$
Solution
(d) $T = \frac{{0.6931 \times 1}}{\lambda } = \frac{{0.6931 \times 1}}{{4.28 \times {{10}^{ – 4}}}}year = 1620\;years$
Standard 12
Physics
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