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13.Nuclei
medium
$10\, gm$ of radioactive material of half-life $15$ year is kept in store for $20$ years. The disintegrated material is ............$gm$
A
$12.5 $
B
$10.5$
C
$6.04$
D
$4.03 $
Solution
(c) Remaining material $N = \frac{{{N_0}}}{{{2^{t/T}}}}$
$ \Rightarrow N = \frac{{10}}{{{{(2)}^{20/15}}}} = \frac{{10}}{{2.15}} = 3.96\;gm$
So decayed material $ = 10 – 3.96 = 6.04\;gm$
Standard 12
Physics
