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9.Straight Line
medium
The diagonals of a parallelogram $PQRS$ are along the lines $x + 3y = 4$ and $6x - 2y = 7$. Then $PQRS$ must be a
A
Rectangle
B
Square
C
Cyclic quadrilateral
D
Rhombus
(IIT-1998)
Solution
(d) ${m_1} = – 1/3$ and ${m_2} = 3$.
Hence lines $x + 3y = 4$ and $6x – 2y = 7$ are perpendicular to each other.
Therefore the paralellogram is rhombus.
Standard 11
Mathematics