9.Straight Line
medium

The diagonals of a parallelogram $PQRS$ are along the lines $x + 3y = 4$ and $6x - 2y = 7$. Then $PQRS$ must be a

A

Rectangle

B

Square

C

Cyclic quadrilateral

D

Rhombus

(IIT-1998)

Solution

(d) ${m_1} = – 1/3$ and ${m_2} = 3$.

Hence lines $x + 3y = 4$ and $6x – 2y = 7$ are perpendicular to each other.

Therefore the paralellogram is rhombus.

Standard 11
Mathematics

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