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Question

Let $P$ be the principal.

S.I. on first year $=P 	imes \frac{10 	imes 1}{100}=\frac{P}{10}$

S.I. on second year $=P 	imes \frac{10 	imes 1}{

Vedclass · Accepted Answer

$8000$

Vedclass · Answer

Let $P$ be the principal.

S.I. on first year $=P 	imes \frac{10 	imes 1}{100}=\frac{P}{10}$

S.I. on second year $=P 	imes \frac{10 	imes 1}{100}=\frac{P}{10}$

Total S.I. $=2 	imes \frac{P}{10}=\frac{P}{5}$

C.I. for 2 year $=P\left(1+\frac{R}{200}ight)^{4}-P$

$=P\left[\left(1+\frac{10}{200}ight)^{4}-1ight]$

$=P\left[\left(1+\frac{5}{100}ight)^{4}-1ight]$

$(2)-(1) \Rightarrow P\left[\left(1+\frac{5}{100}ight)^{4}-1-\frac{1}{5}ight]=124.05$

$P\left[\left(\frac{21}{20}ight)^{4}-\frac{6}{5}ight]=124.05$

Or $P\left[\frac{1,94,481}{1,60,000}-\frac{6}{5}ight]=124.05$

Or $P=\frac{12405}{100} 	imes \frac{1,60,000}{1,94,481-1,92,000}$

$=₹ 8000$

The difference between the simple interest on a certain sum at the rate of $10 \%$ per annum for $2$ years and compound interest which is compounded every $6$ months is ₹ $124.05$ . What is the principal (In ₹) ?

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