The dimension of frac{1}{2} varepsilon_0 E ^2 | vedclass

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Question

Energy, density, of, an ,electric, filed, E, is
${u_E} = \frac{1}{2}{\varepsilon _o}{E^2}$
Where,${\varepsilon _o}$, is, permittivity, of, free, spa

Vedclass · Accepted Answer

$M^1L^{-1}T^{-2}$

Vedclass · Answer

Energy, density, of, an ,electric, filed, E, is
${u_E} = \frac{1}{2}{\varepsilon _o}{E^2}$
Where,${\varepsilon _o}$, is, permittivity, of, free, space
${u_E} = \frac{{Energy}}{{Volume}} = \frac{{M{L^2}{T^{ - 2}}}}{{{L^3}}} = M{L^{ - 1}}{T^{ - 2}}$
Hence, the, dim ension, of, $\frac{1}{2}{\varepsilon _o}{E^2}\,is\,M{L^{ - 1}}{T^{ - 2}}$

The dimension of $\frac{1}{2} \varepsilon_0 E ^2$, where $\varepsilon_0$ is permittivity of free space and $E$ is electric field, is

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