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1.Units, Dimensions and Measurement
easy
પાવરનું પારિમાણિક સૂત્ર શું થાય?
A${M^1}{L^2}{T^{ - 3}}$
B${M^2}{L^1}{T^{ - 2}}$
C${M^1}{L^2}{T^{ - 1}}$
D${M^1}{L^1}{T^{ - 2}}$
Solution
(a) Power = $\frac{{{\rm{Work done}}}}{{{\rm{Time}}}} $$= \left[ {\frac{{M{L^2}{T^{ – 2}}}}{T}} \right] = [M{L^2}{T^{ – 3}}]$
Standard 11
Physics
