Direction (θ ) of vec E at point P due to uniformly charged finite rod will be

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1. Electric Charges and Fields

normal

The direction $(\theta ) $ of $\vec E$ at point $P$ due to uniformly charged finite rod will be

A

at angle $30°$ from $x-$axis

B

$45°$ from $x$ $-$ axis

C

$60°$ from $x$-axis

D

none of these

Solution

The angle suspended by the finite line charge at $P=60^{0}$

So the resultant electric field due to line charge will be at $60 / 2 \Rightarrow 30^{\circ}$ since we can

assume the charge concentrated at the centre of finite line charge.

Standard 12

Physics

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