Two charges $q$ and $3 q$ are separated by a distance ' $r$ ' in air. At a distance $x$ from charge $q$, the resultant electric field is zero. The value of $x$ is :
$\frac{(1+\sqrt{3})}{r}$
$\frac{\mathrm{r}}{3(1+\sqrt{3})}$
$\frac{r}{(1+\sqrt{3})}$
$r(1+\sqrt{3})$
A uniformly charged disc of radius $R$ having surface charge density $\sigma$ is placed in the ${xy}$ plane with its center at the origin. Find the electric field intensity along the $z$-axis at a distance $Z$ from origin :-
Four charges $q, 2q, -4q$ and $2q$ are placed in order at the four corners of a square of side $b$. The net field at the centre of the square is
A charged particle of mass $0.003\, gm$ is held stationary in space by placing it in a downward direction of electric field of $6 \times {10^4}\,N/C$. Then the magnitude of the charge is
The magnitude of electric field intensity $E$ is such that, an electron placed in it would experience an electrical force equal to its weight is given by
In the following four situations charged particles are at equal distance from the origin. Arrange them the magnitude of the net electric field at origin greatest first