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2.Motion in Straight Line
easy
The displacement $(x)$ - time $(t)$ graph of a particle is shown in figure. Which of the following is correct?
A
Particle starts with zero velocity and variable acceleration
B
Particle starts with non-zero velocity and variable acceleration
C
Particle starts with zero velocity and uniform acceleration
D
Particle starts with non-zero velocity and uniform acceleration
Solution
(a)
From the graph it is clear that the $x$ is a function of time and speed/velocity is also changing. So, if velocity is changing then definitely the acceleration also changes with time. So, at $t=0, x=0$, so $v=0$ but it is function of time and hence non-uniform.
Standard 11
Physics
Similar Questions
Refer to the graph in figure. Match the following
| Graph | Characteristics |
| $(A)$ | $(i)$ has $v > 0$ and $a < 0$ throughout |
| $(B)$ | $(ii)$ has $x > 0,$ throughout and has a point with $v = 0$ and a point with $a = 0$ |
| $(C)$ | $(iii)$ has a point with zero displacement for $t > 0$ |
| $(D)$ | $(iv)$ has $v < 0$ and $a > 0$ |
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