2.Motion in Straight Line
medium

એક કણનું સ્થાનાંતર $y = a + bt + c{t^2} - d{t^4}$ છે,તો તેનો શરૂઆતનો વેગ અને પ્રવેગ અનુક્રમે

A

$b,\, - 4d$

B

$ - b,\,2c$

C

$b,\,2c$

D

$2c,\, - 4d$

Solution

(c) $y = a + bt + c{t^2} – d{t^4}$

$\therefore \;v = \frac{{dy}}{{dt}} = b + 2ct – 4d{t^3}$ and $a = \frac{{dv}}{{dt}} = 2c – 12d{t^2}$

Hence, at $t = 0$, $v_{initial} \,= b$ and $a_{initial}$ $= 2c$.

Standard 11
Physics

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