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2.Motion in Straight Line
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The displacement-time graph for two particles $A$ and $B$ is as follows. The ratio $\frac{v_A}{v_B}$ is
A
$1: 2$
B
$1: \sqrt{3}$
C
$\sqrt{3}: 1$
D
$1: 3$
Solution
(d)
The slope of line $A$ is $\tan 30^{\circ}$ and $B=\tan 60^{\circ}$
$\frac{v_A}{v_B}=\frac{\tan 30^{\circ}}{\tan 60^{\circ}}=\frac{\frac{1}{\sqrt{3}}}{\sqrt{3}}=\frac{1}{3} \Rightarrow v_A: v_B=1: 3$
Standard 11
Physics
