The dissolution of $Al(OH)_3$ by a solution of $NaOH$ results in the formation of
$[Al(H_2O)_4(OH)_2]^+$
$[Al(H_2O)_3(0H)_3]$
$[Al(H_2O)_2(OH)_4]^-$
$[Al(H_2O)_6(OH)_3]$
Aluminium trifluoride is insoluble in anhydrous $HF$ but dissolves on addition of $NaF$. Aluminium trifluoride precipitates out of the resulting solution when gaseous $BF $$_{3}$ is bubbled through. Give reasons.
Given below are two statements :
Statement $I:$ Upon heating a borax bead dipped in cupric sulphate in a luminous flame, the colour of the bead becomes green.
Statement $II:$ The green colour observed is due to the formation of copper(I) metaborate.
In the light of the above statements, choose the most appropriate answer from the options given below :
Alumina is insoluble in water because
A group $13$ element $'X'$ reacts with chlorine gas to produce a compound $XCl_3. XCl_3$ is electron deficient and easily reacts with $NH_3$ to form $Cl_3X \leftarrow NH_3$ adduct, however, $XCl_3$ does not dimerize. $X$ is
The formation of molecular complex $BF_3 - NH_3$ results in a change in hybridization of boron