The dissolution of Al(OH)_3 by a solution of | vedclass

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Question

$Al(OH)_3$ dissolves in $NaOH$ solution to give $Al(OH)_4^-$ ion which is supposed to have the octahedral complex species $[Al(OH)_4(H_2O)_2]^-$ in aq

Vedclass · Accepted Answer

$[Al(H_2O)_2(OH)_4]^-$

Vedclass · Answer

$Al(OH)_3$ dissolves in $NaOH$ solution to give $Al(OH)_4^-$ ion which is supposed to have the octahedral complex species $[Al(OH)_4(H_2O)_2]^-$ in aqueous solution.

$Al{\left( {OH} ight)_3} + NaOH\left( {aq} ight) 	o {\left[ {Al{{\left( {OH} ight)}_4}{{\left( {{H_2}O} ight)}_2}} ight]^ - }\left( {aq} ight) + N{a^ + }\left( {aq} ight)$

The dissolution of $Al(OH)_3$ by a solution of $NaOH$ results in the formation of

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