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7.Gravitation
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The distance of neptune and saturn from sun are nearly ${10^{13}}$ and ${10^{12}}$ meters respectively. Assuming that they move in circular orbits, their periodic times will be in the ratio
A
$\sqrt {10} $
B
$100$
C
$10\sqrt {10} $
D
$1/\sqrt {10} $
(AIPMT-1994)
Solution
(c) $\frac{{{T_1}}}{{{T_2}}} = {\left( {\frac{{{R_1}}}{{{R_2}}}} \right)^{3/2}} $
$= {\left( {\frac{{{{10}^{13}}}}{{{{10}^{12}}}}} \right)^{3/2}}$
$= {(1000)^{1/2}}$
$ = 10\sqrt {10} $
Standard 11
Physics