The distance of two points on the axis of a m | vedclass

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(c)$\frac{{{B_1}}}{{{B_2}}} = \frac{{{d_1}}}{{{d_2}}}{\left( {\frac{{d_2^2 - {l^2}}}{{d_1^2 - {l^2}}}} \right)^2} \Rightarrow \frac{{12.5}}{1} = \frac

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$10$

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(c)$\frac{{{B_1}}}{{{B_2}}} = \frac{{{d_1}}}{{{d_2}}}{\left( {\frac{{d_2^2 - {l^2}}}{{d_1^2 - {l^2}}}} \right)^2} \Rightarrow \frac{{12.5}}{1} = \frac{{10}}{{20}}{\left( {\frac{{400 - {l^2}}}{{100 - {l^2}}}} \right)^2}$
$ \Rightarrow l = 5\;cm$
Hence length of magnet $ = 2l = 10\;cm$

The distance of two points on the axis of a magnet from its centre is $10 \,cm$ and $20 \,cm$ respectively. The ratio of magnetic intensity at these points is $12.5 : 1. $ The length of the magnet will be......$cm$

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