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8.Electromagnetic waves
hard
The electric field intensity produced by the radiation coming from a $100\, W$ bulb at a distance of $3\, m$ is $E$. The electric field intensity produced by the radiation coming from $60\, W$ at the same distance is $\sqrt{\frac{x}{5}} E$. Where the value of $x=......... .$
A
$1$
B
$3$
C
$6$
D
$9$
(JEE MAIN-2021)
Solution
$c \in_{0} E ^{2}=\frac{100}{4 \pi \times 3^{2}}$
$c \epsilon_{0}\left(\sqrt{\frac{ x }{5}} E \right)^{2}=\frac{60}{4 \pi \times 3^{2}}$
$\Rightarrow \frac{ x }{5}=\frac{3}{5}$
$\Rightarrow x =3$
Standard 12
Physics
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