8.Electromagnetic waves
hard

The electric field intensity produced by the radiation coming from a $100\, W$ bulb at a distance of $3\, m$ is $E$. The electric field intensity produced by the radiation coming from $60\, W$ at the same distance is $\sqrt{\frac{x}{5}} E$. Where the value of $x=......... .$

A

$1$

B

$3$

C

$6$

D

$9$

(JEE MAIN-2021)

Solution

$c \in_{0} E ^{2}=\frac{100}{4 \pi \times 3^{2}}$

$c \epsilon_{0}\left(\sqrt{\frac{ x }{5}} E \right)^{2}=\frac{60}{4 \pi \times 3^{2}}$

$\Rightarrow \frac{ x }{5}=\frac{3}{5}$

$\Rightarrow x =3$

Standard 12
Physics

Similar Questions

Start a Free Trial Now

Confusing about what to choose? Our team will schedule a demo shortly.