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8.Electromagnetic waves
easy
The magnetic field in a plane electromagnetic wave is given by, $B=3.01 \times 10^{-7} \sin \left(6.28 \times 10^2 \times+2.2 \times 10^{10} t\right) \,T$. [where $x$ in $cm$ and $t$ in second]. The wavelength of the given wave is ....... $cm$
A
$1$
B
$628$
C
$1.129$
D
$314$
Solution
(a)
$\bar{B}=3.01 \times 10^{-7} \sin \left(6.28 \times 10^2 x+2.2 \times 10^{10} t\right) \,T$
$k=6.28 \times 10^2$
$\omega=2.2 \times 10^{10}$
$k=\frac{2 \pi}{\lambda}$
$\therefore \lambda=\frac{2 \pi}{6.28 \times 10^2}=10^{-2} \,m$
Standard 12
Physics
