The electric potential $V$ at any point $O$ ($x, y, z$ all in metre) in space is given by $V=4x^2\, volt$. The electric field at the point $(1\,m, 0, 2\,m)$ in $volt/meter$ is

A given charge situated at a distance $r$ from an electric dipole on it axis experiences a force $F$. If the distance of the charge from the dipole is doubled, the force acting on the charge will be

A capacitor of capacitance $1$ $\mu F$ with stands the maximum voltages $6$ $KV$ while a capacitor of capacitance $2.0$ $\mu F$ with stands the maximum voltage $=$ $4\,KV$. if the two capacitors are connected in series, then the two capacitors combined can take up a maximum voltage of......$KV$

The adjoining diagram shows the electric lines of force emerging from a charged body. If the electric fields at $A$ and $B$ are $E_A$ and $E_B$ respectively and the distance between them is $r$, then

The electric field $\vec E$  between two points is constant in both magnitude and direction. Consider a path of length d at an angle $\theta  = 60^o$  with respect to field lines shown in figure. The potential difference between points  $1$ and $2$  is

Find capacitance across $AB$