If distance between two equal point charge is doubled then what would happen to force between them ?

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1. Electric Charges and Fields

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If the distance between two equal point charge is doubled then what would happen to the force between them ?

$F$

$\frac{F}{2}$

$\frac{F}{4}$

$\frac{F}{3}$

Solution

$F = \frac{1}{{4\pi { \in _0}}}\frac{{{q^2}}}{{{r^2}}} \Rightarrow F' = \frac{1}{{4\pi { \in _0}}}\frac{{{q^2}}}{{{{\left( {2r} \right)}^2}}} = \frac{F}{4}$

Standard 12

Physics

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A series combination of $n_1$ capacitors, each of value $C_1$, is charged by a source of potential difference $4V$. When another parallel combination of $n_2$ capacitors, each of value $C_2$, is charged by a source of potential difference $V$ , it has the same (total) energy stored in it, as the first combination has. The value of $C_2$ , in terms of $C_1$, is then

normal

If the distance between two equal point charge is doubled then what would happen to the force between them ?

Solution

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