If the distance between two equal point charg | vedclass

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Question

$F = \frac{1}{{4\pi { \in _0}}}\frac{{{q^2}}}{{{r^2}}} \Rightarrow F' = \frac{1}{{4\pi { \in _0}}}\frac{{{q^2}}}{{{{\left( {2r} \right)}^2}}} = \f

Vedclass · Accepted Answer

$\frac{F}{4}$

Vedclass · Answer

$F = \frac{1}{{4\pi { \in _0}}}\frac{{{q^2}}}{{{r^2}}} \Rightarrow F' = \frac{1}{{4\pi { \in _0}}}\frac{{{q^2}}}{{{{\left( {2r} \right)}^2}}} = \frac{F}{4}$

If the distance between two equal point charge is doubled then what would happen to the force between them ?

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