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2. Electric Potential and Capacitance
easy
The energy of a charged capacitor is given by the expression ($q$= charge on the conductor and $C$ = its capacity)
A
$\frac{{{q^2}}}{{2C}}$
B
$\frac{{{q^2}}}{C}$
C
$2qC$
D
$\frac{q}{{2{C^2}}}$
Solution
$q = CV$ and $U = \frac{1}{2}C{V^2} = \frac{{{q^2}}}{{2C}}$
Standard 12
Physics