2. Electric Potential and Capacitance
easy

The energy of a charged capacitor is given by the expression ($q$= charge on the conductor and $C$ = its capacity)

A

$\frac{{{q^2}}}{{2C}}$

B

$\frac{{{q^2}}}{C}$

C

$2qC$

D

$\frac{q}{{2{C^2}}}$

Solution

 $q = CV$ and $U = \frac{1}{2}C{V^2} = \frac{{{q^2}}}{{2C}}$

Standard 12
Physics

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