A condenser of capacity ${C_1}$ is charged to a potential ${V_0}$. The electrostatic energy stored in it is ${U_0}$. It is connected to another uncharged condenser of capacity ${C_2}$ in parallel. The energy dissipated in the process is
$\frac{{{C_2}}}{{{C_1} + {C_2}}}{U_0}$
$\frac{{{C_1}}}{{{C_1} + {C_2}}}{U_0}$
$\left( {\frac{{{C_1} - {C_2}}}{{{C_1} + {C_2}}}} \right){U_0}$
$\frac{{{C_1}{C_2}}}{{2({C_1} + {C_2})}}{U_0}$
In a uniform electric field, a cube of side $1\ cm$ is placed. The total energy stored in the cube is $8.85\ μJ$ . The electric field is parallel to four of the faces of the cube. The electric flux through any one of the remaining two faces is
A capacitor $C$ is charged to a potential difference $V$ and battery is disconnected. Now if the capacitor plates are brought close slowly by some distance :
A $600\; pF$ capacitor is charged by a $200\; V$ supply. It is then disconnected from the supply and is connected to another uncharged $600\; pF$ capacitor. How much electrostatic energy is lost in the process?
The work done in placing a charge of $8 \times {10^{ - 18}}$ coulomb on a condenser of capacity $100\, micro-farad$ is
The energy stored in a condenser of capacity $C$ which has been raised to a potential $V$ is given by