A condenser of capacity ${C_1}$ is charged to a potential ${V_0}$. The electrostatic energy stored in it is ${U_0}$. It is connected to another uncharged condenser of capacity ${C_2}$ in parallel. The energy dissipated in the process is
$\frac{{{C_2}}}{{{C_1} + {C_2}}}{U_0}$
$\frac{{{C_1}}}{{{C_1} + {C_2}}}{U_0}$
$\left( {\frac{{{C_1} - {C_2}}}{{{C_1} + {C_2}}}} \right){U_0}$
$\frac{{{C_1}{C_2}}}{{2({C_1} + {C_2})}}{U_0}$
Two capacitors of capacitances $C$ and $2\, C$ are charged to potential differences $V$ and $2\, V$, respectively. These are then connected in parallel in such a manner that the positive terminal of one is connected to the negative terminal of the other. The final energy of this configuration is$.....CV^2$
A $4 \;\mu\, F$ capacitor is charged by a $200\; V$ supply. It is then disconnected from the supply, and is connected to another uncharged $2 \;\mu\, F$ capacitor. How much electrostatic energy of the first capacitor is lost in the form of heat and electromagnetic radiation?
The energy stored in a condenser is in the form of
Charge $'q'$ on a capacitor varies with voltage $'V'$ as shown. The area of $\Delta OPM$ represents
If the potential of a capacitor having capacity of $6\,\mu F$ is increased from $10\, V$ to $20\, V$, then increase in its energy will be