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5.Work, Energy, Power and Collision
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The energy required to accelerate a car from $10 \,m/s$ to $20\, m/s$ is how many times the energy required to accelerate the car from rest to $10\, m/s$
A
Equal
B
$4 $ times
C
$2$ times
D
$3$ times
Solution
(d) Kinetic energy for first condition
=$\frac{1}{2}m\left( {v_2^2 – v_1^2} \right) = \frac{1}{2}m\left( {{{20}^2} – {{10}^2}} \right)$= $150\;mJ$
$K.E.$ for second condition = $\frac{1}{2}m\left( {{{10}^2} – {0^2}} \right) = 50mJ$
$\therefore \frac{{(K.E.)_I}}{{(K.E.)_{II}}} = \frac{{150m}}{{50m}} = 3$
Standard 11
Physics
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