A particle of mass m at rest is acted upon by | vedclass

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Question

$\mathrm{v}=\mathrm{u}+\mathrm{at}$               $P=m a$

$\mathrm{v}=\mathrm

Vedclass · Accepted Answer

$\frac{{{P^2}{t^2}}}{2m}$

Vedclass · Answer

$\mathrm{v}=\mathrm{u}+\mathrm{at}$               $P=m a$

$\mathrm{v}=\mathrm{at} \quad \ldots(1)$            $a=\frac{P}{m} \ldots(2)$

$v = \frac{p}{m} 	imes t$

$\mathrm{KE}=\frac{1}{2} \mathrm{mv}^{2}=\frac{1}{2} 	imes \mathrm{m} 	imes \frac{\mathrm{P}^{2}}{\mathrm{m}^{2}} 	imes \mathrm{t}^{2}$

$\mathrm{KE}=\frac{\mathrm{P}^{2} \mathrm{t}^{2}}{2 \mathrm{m}}$

A particle of mass $m$ at rest is acted upon by a force $P$ for a time $t.$ Its kinetic energy after an interval $t$ is

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