The equation $\sin x\cos x = 2$ has
One solution
Two solutions
Infinite solutions
No solutions
(d) $\sin x\cos x = 2$ or $\sin 2x = 4$, which is impossible.
Find the general solution of $\cos ec\, x=-2$
The general solution of $\sin x – 3\sin 2x + \sin 3x = $ $\cos x – 3\cos 2x + \cos 3x$ is
If $2(\sin x – \cos 2x) – \sin 2x(1 + 2\sin x)2\cos x = 0$ then
If$\cos 6\theta + \cos 4\theta + \cos 2\theta + 1 = 0$, where $0 < \theta < {180^o}$, then $\theta =$
If $\cos \,\alpha + \cos \,\beta = \frac{3}{2}$ and $\sin \,\alpha + \sin \,\beta = \frac{1}{2}$ and $\theta $ is the the arithmetic mean of $\alpha $ and $\beta $ , then $\sin \,2\theta + \cos \,2\theta $ is equal to
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