Equation of a curve is given as y=x^2+2-3 x . curve intersects x -axis at

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The equation of a curve is given as $y=x^2+2-3 x$. The curve intersects the $x$-axis at

A

$(1,0)$

B

$(2,0)$

C

Both $(1)$ and $(2)$

D

No where

Solution

(c)

At $x$-axis, $y=0$ so $x^2+2-3 x=0 \Rightarrow x=1$ and 2 Therefore curve intersects the $x$-axis at $(1,0)$ and $(2,0)$

Standard 11

Physics

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