Side of a square is increasing at rate of 0.2,cm / s . rate of increase of perimeter w.r.t. time is

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The side of a square is increasing at the rate of $0.2\,cm / s$. The rate of increase of perimeter w.r.t. time is $...........\,cm / s$

A

$0.2$

B

$0.4$

C

$0.6$

D

$0.8$

Solution

(d)

If side $= a$, then rate of increase of perimeter w.r.t.$\text { time }=4\left(\frac{ da }{ dt }\right)=4(0.2)=0.8\,cm / s$

Standard 11

Physics

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