Equation of tangent to circle {x^2} + {y^2} - 2x - 4y - 4 = 0 which is perpendicular to 3x - 4y - 1

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10-1.Circle and System of Circles

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The equation of the tangent to the circle ${x^2} + {y^2} - 2x - 4y - 4 = 0$ which is perpendicular to $3x - 4y - 1 = 0$, is

A

$4x + 3y - 5 = 0$

B

$4x + 3y + 25 = 0$

C

$4x - 3y + 5 = 0$

D

$4x + 3y - 25 = 0$

Solution

(d) Tangent is of form $4x + 3y + c = 0$.

From condition of tangency to the circle, we get $c = – 25$.

Hence equation is $4x + 3y – 25 = 0$.

Standard 11

Mathematics

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(IIT-2007)