The angle between the tangents from (alpha ,b | vedclass

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Question

(c) $	an \frac{	heta }{2} = \frac{{C{T_1}}}{{P{T_1}}}$

$= \frac{a}{{\sqrt {{\alpha ^2} + {\beta ^2} - {a^2}} }}$

$\frac{	heta }{2} = {	an ^{

Vedclass · Accepted Answer

$2{	an ^{ - 1}}\left( {\frac{a}{{\sqrt {{\alpha ^2} + {\beta ^2} - {a^2}} }}} ight)$

Vedclass · Answer

(c) $	an \frac{	heta }{2} = \frac{{C{T_1}}}{{P{T_1}}}$

$= \frac{a}{{\sqrt {{\alpha ^2} + {\beta ^2} - {a^2}} }}$

$\frac{	heta }{2} = {	an ^{ - 1}}\frac{a}{{\sqrt {{\alpha ^2} + {\beta ^2} - {a^2}} }} $

$\Rightarrow 	heta = 2{	an ^{ - 1}}\frac{a}{{\sqrt {{\alpha ^2} + {\beta ^2} - {a^2}} }}$.

The angle between the tangents from $(\alpha ,\beta )$to the circle ${x^2} + {y^2} = {a^2}$, is

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