$cos^273^o + cos^247^o + (cos73^o . cos47^o )$ =
$cos^273^o + cos^247^o + (cos73^o . cos47^o )$ =
- A
$1/4$
- B
$1/2$
- C
$3/4$
- D
$1$
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સાબિત કરો કે : $\cos 4 x=1-8 \sin ^{2} x \cos ^{2} x$
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- [IIT 1964]
$\frac{1}{4} \,\,tan \frac{\pi}{8} +\frac{1}{8} \,\,tan \frac{\pi}{16}+\frac{1}{16} \,\,tan \frac{\pi}{32}+.\,.\,.\,\infty $ પદ =
$\frac{1}{4} \,\,tan \frac{\pi}{8} +\frac{1}{8} \,\,tan \frac{\pi}{16}+\frac{1}{16} \,\,tan \frac{\pi}{32}+.\,.\,.\,\infty $ પદ =