tan frac{A}{2} = . . . | vedclass

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Question

(c) $	an \left( {\frac{A}{2}} ight) $

$= \frac{{\sin (A/2)}}{{\cos (A/2)}} $

$= \pm \sqrt {\frac{{(1 - \cos A)/2}}{{(1 + \cos A)/2}}} $

$=

Vedclass · Accepted Answer

$ \pm \sqrt {\frac{{1 - \cos A}}{{1 + \cos A}}} $

Vedclass · Answer

(c) $	an \left( {\frac{A}{2}} ight) $

$= \frac{{\sin (A/2)}}{{\cos (A/2)}} $

$= \pm \sqrt {\frac{{(1 - \cos A)/2}}{{(1 + \cos A)/2}}} $

$= \pm \sqrt {\frac{{1 - \cos A}}{{1 + \cos A}}} $.

$\tan \frac{A}{2} = . . .$

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