$\tan \frac{A}{2} = . . .$
$\tan \frac{A}{2} = . . .$
- A
$ \pm \sqrt {\frac{{1 - \sin A}}{{1 + \sin A}}} $
- B
$ \pm \sqrt {\frac{{1 + \sin A}}{{1 - \sin A}}} $
- C
$ \pm \sqrt {\frac{{1 - \cos A}}{{1 + \cos A}}} $
- D
$ \pm \sqrt {\frac{{1 + \cos A}}{{1 - \cos A}}} $
Similar Questions
જો $x + y + z = {180^o},$ તો $\cos 2x + \cos 2y - \cos 2z = . . . .$
જો $x + y + z = {180^o},$ તો $\cos 2x + \cos 2y - \cos 2z = . . . .$
$\frac{{4\sin {9^o}\sin {{21}^o}\sin {{39}^o}\sin {{51}^o}\sin {{69}^o}\sin {{81}^o}}}{{\sin {{54}^o}}}$ =
$\frac{{4\sin {9^o}\sin {{21}^o}\sin {{39}^o}\sin {{51}^o}\sin {{69}^o}\sin {{81}^o}}}{{\sin {{54}^o}}}$ =
$\cos \frac{\pi }{7}\cos \frac{{2\pi }}{7}\cos \frac{{4\pi }}{7} = $
$\cos \frac{\pi }{7}\cos \frac{{2\pi }}{7}\cos \frac{{4\pi }}{7} = $
$x$ ............ કિમત માટે $x = 1 - x + x^2 - x^3 + x^4 - x^5 + ......... \infty$ થાય
$x$ ............ કિમત માટે $x = 1 - x + x^2 - x^3 + x^4 - x^5 + ......... \infty$ થાય
જો $\cos \left( {\frac{{\alpha - \beta }}{2}} \right) = 2\cos \left( {\frac{{\alpha + B}}{2}} \right)$, તો $\tan \frac{\alpha }{2}\tan \frac{\beta }{2} = . . .$
જો $\cos \left( {\frac{{\alpha - \beta }}{2}} \right) = 2\cos \left( {\frac{{\alpha + B}}{2}} \right)$, તો $\tan \frac{\alpha }{2}\tan \frac{\beta }{2} = . . .$