The excess pressure inside a soap bubble is thrice the excess pressure inside a second soap bubble. The ratio between the volume of the first and the second bubble is:
$1: 9$
$1: 3$
$1: 81$
$1: 27$
If pressure at half the depth of a lake is equal to $2/3$ pressure at the bottom of the lake then what is the depth of the lake...... $m$
If the surface tension of a soap solution is $0.03\, MKS$ units, then the excess of pressure inside a soap bubble of diameter $6 \,mm$ over the atmospheric pressure will be
In capillary pressure below the curved surface of water will be
A soap bubble in a form of circular tube having radius of curvature $R$ and radius of curvature perpendicular to it is $5R$ . Find the excess pressure in the bubble :
The surface tension and vapour pressure of water at $20^{°}$ $\mathrm{C}$ is $7.28 \times {10^{ - 2}}\,{\rm{N/m}}$ and $2.33 \times {10^3}\,{{\rm{P}}_{\rm{a}}}$ respectively. What is the radius of the smallest spherical water droplet which can form without evaporating at $20^{°}$ $\mathrm{C}$ ?