3-1.Vectors
easy

व्यंजक $\left( {\frac{1}{{\sqrt 2 }}\hat i + \frac{1}{{\sqrt 2 }}\hat j} \right)$ है

A

इकाई सदिश

B

शून्य सदिश

C

$\sqrt 2 $ परिमाण का सदिश

D

अदिश

Solution

(a) $\vec P = \frac{1}{{\sqrt 2 }}\hat i + \frac{1}{{\sqrt 2 }}\hat j$

$|\vec P| = \sqrt {{{\left( {\frac{1}{{\sqrt 2 }}} \right)}^2} + {{\left( {\frac{1}{{\sqrt 2 }}} \right)}^2}} = 1$

 यह एक एकांक सदिश है।

Standard 11
Physics

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