Gujarati
Hindi
2. Electric Potential and Capacitance
medium

The figure shows a family of parallel equipotential surfaces and four paths along which an electron is made to move from one surface to another as shown in the figur
$(I)$ What is the direction of the electric field ?
$(II)$ Rank the paths according to magnitude of work done, greatest first

A

Righward ; $4 > 3 > 2 > 1$

B

Leftward ; $1 > 2 > 3 > 4$

C

Rightward ; $3 = 4 > 2 = 1$

D

Left ward ; $1 > 2 > 3 = 4$

Solution

Along the direction of electric field, electric potential decreases, hence it should be from left to right.

Change in potential of path $3$ and $4$ is greater hence

$3=4>2=1$

Standard 12
Physics

Similar Questions

Start a Free Trial Now

Confusing about what to choose? Our team will schedule a demo shortly.