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2. Electric Potential and Capacitance
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The figure shows a family of parallel equipotential surfaces and four paths along which an electron is made to move from one surface to another as shown in the figur
$(I)$ What is the direction of the electric field ?
$(II)$ Rank the paths according to magnitude of work done, greatest first

A
Righward ; $4 > 3 > 2 > 1$
B
Leftward ; $1 > 2 > 3 > 4$
C
Rightward ; $3 = 4 > 2 = 1$
D
Left ward ; $1 > 2 > 3 = 4$
Solution
Along the direction of electric field, electric potential decreases, hence it should be from left to right.
Change in potential of path $3$ and $4$ is greater hence
$3=4>2=1$
Standard 12
Physics
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