Figure shows a process AB undergone by 2 moles of an ideal diatomic gas. process AB is in such

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11.Thermodynamics

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The figure shows a process $AB$ undergone by $2$ moles of an ideal diatomic gas. The process $AB$ is in such a way that $VT =$ constant. $T_1 = 300 K $and $T_2 = 500 K$ ( $R = $ gas constant)

A

The molar heat capacity of gas in the process $A \rightarrow B$ is $5\frac{R}{2} J/mol-K$

B

The molar heat capacity of gas in the process $A \rightarrow B$ is $R J/mol-K$

C

The work done by the gas is $-400R J$

D

The work done by the gas is $-200R J$

Solution

$\mathrm{VT}=\mathrm{C}_{0}$

$\mathrm{PV}^{2}=\mathrm{C}_{0}, \quad \mathrm{x}=2$

$C=C_{v}+\frac{R}{1-r}=\left(\frac{3 R}{2}\right)$

$W=\left[\frac{n R \Delta T}{(-x)}\right]=\frac{2 R \times 200}{(1-2)}=-400 R$

Standard 11

Physics

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