9-1.Fluid Mechanics
medium

${V_0}$ आयतन व ${d_0}$घनत्व का पिण्ड, $d $ घनत्व वाले द्रव में तैर रहा है। पिण्ड के आयतन का वह भाग क्या होगा जो द्रव की सतह के ऊपर है

A

$\frac{{{d_0}}}{d}$

B

$\frac{{d{d_0}}}{{d + {d_0}}}$

C

$\frac{{d - {d_0}}}{d}$

D

$\frac{{d{d_0}}}{{d - {d_0}}}$

Solution

(c)तैरने के लिये${V_0}{d_0}g = {V_{in}}\;d\;g$ ==> ${V_{in}} = {V_0}\frac{{{d_0}}}{d}$
${V_{out}} = {V_0} – {V_{in}} = {V_0} – {V_0}\frac{{{d_0}}}{d}$$ = {V_0}\left[ {\frac{{d – {d_0}}}{d}} \right]$
==> $\frac{{{V_{out}}}}{{{V_0}}} = \frac{{d – {d_0}}}{d}$

Standard 11
Physics

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