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13.Nuclei
medium
The graph in figure shows how the count-rate $A$ of a radioactive source as measured by a Geiger counter varies with time $t.$ The relationship between $A$ and $t$ is : $($ Assume $ln\,\, 12 = 2.6)$
A
$A = 2.6 \,e^{-10t}$
B
$A = 12 \,e^{-10t}$
C
$A = 2.6 \,e^{-0.1t}$
D
$A = 1.2 \,e^{-0.1t}$
Solution
$\mathrm{y}=\mathrm{mx}+\mathrm{C}$
$\ln A=2.6-\frac{t}{10}$
$A=e^{2 \cdot 6} e^{-t}=12 e^{-t / 10}$
Standard 12
Physics
