The greatest height to which a man can throw | vedclass

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Question

(c) For greatest height $	heta = 90^&deg;$

${H_{\max }} = \frac{{{u^2}{{\sin }^2}(90^\circ )}}{{2g}} = \frac{{{u^2}}}{{2g}} = h$ (given)

${R_{\

Vedclass · Accepted Answer

$2h$

Vedclass · Answer

(c) For greatest height $	heta = 90^&deg;$

${H_{\max }} = \frac{{{u^2}{{\sin }^2}(90^\circ )}}{{2g}} = \frac{{{u^2}}}{{2g}} = h$ (given)

${R_{\max }} = \frac{{{u^2}{{\sin }^2}2(45^\circ )}}{g} = \frac{{{u^2}}}{g} = 2h$

The greatest height to which a man can throw a stone is $h$. The greatest distance to which he can throw it, will be

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