Greatest height to which a man can throw a stone is h . greatest distance to which he can throw it,

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3-2.Motion in Plane

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The greatest height to which a man can throw a stone is $h$. The greatest distance to which he can throw it, will be

A

$h/2$

B

$h$

C

$2h$

D

$3h$

Solution

(c) For greatest height $\theta = 90^°$

${H_{\max }} = \frac{{{u^2}{{\sin }^2}(90^\circ )}}{{2g}} = \frac{{{u^2}}}{{2g}} = h$ (given)

${R_{\max }} = \frac{{{u^2}{{\sin }^2}2(45^\circ )}}{g} = \frac{{{u^2}}}{g} = 2h$

Standard 11

Physics

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