Two radioactive elements A and B initially ha | vedclass

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Question

$T_{1 / 2}(A)=T_{w N}(B)$

$\frac{\ln 2}{\lambda_{ A }}=\frac{1}{\lambda_{ B }}$

$\lambda_{ A }=\lambda_{ B } \ell 2$

Vedclass · Accepted Answer

$\lambda_{ A }=\lambda_{ B } \ln 2$

Vedclass · Answer

$T_{1 / 2}(A)=T_{w N}(B)$

$\frac{\ln 2}{\lambda_{ A }}=\frac{1}{\lambda_{ B }}$

$\lambda_{ A }=\lambda_{ B } \ell 2$

Two radioactive elements $A$ and $B$ initially have same number of atoms. The half life of $A$ is same as the average life of $B$. If $\lambda_A$ and $\lambda_B$ are decay constants of $A$ and $B$ respectively, then choose the correct relation from the given options.