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13.Nuclei
medium
The half life period of a radioactive substance is $5\, min$. The amount of substance decayed in $20\, min$ will be..........$\%$
A
$93.75$
B
$75$
C
$25$
D
$6.25$
Solution
(a) Number of half lives in $20\, min = n = \frac{{20}}{5} = 4$
Fraction of material remains after four half lives $ = \frac{1}{{16}}$
Hence fraction that decays $ = 1 – \frac{1}{{16}} = \frac{{15}}{{16}} = 93.75\% $
Standard 12
Physics