Gujarati
10-2.Transmission of Heat
easy

The heat is flowing through a rod of length $50 cm$ and area of cross-section $5c{m^2}$. Its ends are respectively at ${25^o}C$ and ${125^o}C$. The coefficient of thermal conductivity of the material of the rod is $0.092 kcal/m×s×^\circ C$. The temperature gradient in the rod is

A

${2^o}C/cm$

B

${2^o}C/m$

C

${20^o}C/cm$

D

${20^o}C/m$

Solution

(a) Temperature gradient $\frac{{d\theta }}{{dx}} = \frac{{{{(125 – 25)}^o}C}}{{50\;cm}} = 2^\circ C/cm$

Standard 11
Physics

Similar Questions

Start a Free Trial Now

Confusing about what to choose? Our team will schedule a demo shortly.