Initial speed of a projectile fired from ground is u . At highest point during its motion, speed of

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3-2.Motion in Plane

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The initial speed of a projectile fired from ground is $u$. At the highest point during its motion, the speed of projectile is $\frac{\sqrt{3}}{2} u$. The time of flight of the projectile is:

A

$\frac{ u }{2 g }$

B

$\frac{ u }{ g }$

C

$\frac{2 u }{ g }$

D

$\frac{\sqrt{3} u }{ g }$

(JEE MAIN-2023)

Solution

$u \cos \theta=\frac{\sqrt{3} u }{2} \Rightarrow \cos \theta=\frac{\sqrt{3}}{2}$

$\Rightarrow \theta=30^{\circ}$

$T =\frac{2 u \sin 30^{\circ}}{ g }=\frac{ u }{ g }$

Standard 11

Physics

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