11.Thermodynamics
normal

The internal energy change in a system that has absorbed $2\, k\,cals$ of heat and done $500\, J$ of work is ...... $J$

A

$6400$

B

$5400$

C

$7900$

D

$8900$

Solution

According to first law of thermodynamics

$\mathrm{Q} =\Delta \mathrm{U}+\mathrm{W} $

$\Delta \mathrm{U} =\mathrm{Q}-\mathrm{W} $

$=2 \times 4.2 \times 1000-500 $

$=8400-500 $

$=7900 \mathrm{J}$

Standard 11
Physics

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