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11.Thermodynamics
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The internal energy change in a system that has absorbed $2\, k\,cals$ of heat and done $500\, J$ of work is ...... $J$
A
$6400$
B
$5400$
C
$7900$
D
$8900$
Solution
According to first law of thermodynamics
$\mathrm{Q} =\Delta \mathrm{U}+\mathrm{W} $
$\Delta \mathrm{U} =\mathrm{Q}-\mathrm{W} $
$=2 \times 4.2 \times 1000-500 $
$=8400-500 $
$=7900 \mathrm{J}$
Standard 11
Physics
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