The kinetic energy K of a particle moving in | vedclass

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Question

$\mathrm{k}=\mathrm{as}^{2} \Rightarrow \frac{1}{2} \mathrm{mv}^{2}=\mathrm{as}^{2}$

$\mathrm{v}^{2}=\frac{2 \mathrm{a}}{\mathrm{m}} \mathrm{s}^{2}

Vedclass · Accepted Answer

$2\,as$

Vedclass · Answer

$\mathrm{k}=\mathrm{as}^{2} \Rightarrow \frac{1}{2} \mathrm{mv}^{2}=\mathrm{as}^{2}$

$\mathrm{v}^{2}=\frac{2 \mathrm{a}}{\mathrm{m}} \mathrm{s}^{2}$

differentiate $w.r. t.$ time

$2 \mathrm{v} \frac{\mathrm{dv}}{\mathrm{dt}}=\frac{2 \mathrm{a}}{\mathrm{m}} 	imes 2 \mathrm{s} \frac{\mathrm{ds}}{\mathrm{dt}}$

$\mathrm{F}=\mathrm{m} \frac{\mathrm{dv}}{\mathrm{dt}}=2 \mathrm{as}$

The kinetic energy $K$ of a particle moving in a straight line depends upon the distance $s$ as $K = as^2$. The force acting on the particle is

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