For a particle moving under action of a variable force, kinetic energy-position graph is given, then

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5.Work, Energy, Power and Collision

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For a particle moving under the action of a variable force, kinetic energy-position graph is given, then

A

At $A$ particle is decelerating

B

At $B$ particle is accelerating

C

At $C$ particle has maximum velocity

D

At $D$ particle has maximum acceleration

Solution

(d)

$F . d x=d K$

$\frac{d K}{d x}=F$

$\Rightarrow$ Slope of $K-x$ curve gives force

So slope is max at $D$, hence acceleration is maximum at $D$

Standard 11

Physics

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